Good try, Oliver!
Oooo! Oooo! Circle inscribed in a square! I used to know this stuff. The side of the box equals the diameter of the circle, so ½S = the radius. The two dimensional area is πr² and we multiply that by the thickness of the cat to get the volume! How many catnip mousies in a square centimeter? Any help here? Anyone?Sort of a circle..
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I'd say one catnip mouse would have a surface area of about 200 cm squared... hmm. Is a mouse more of a cylinder or a rectangular prism... ?Oooo! Oooo! Circle inscribed in a square! I used to know this stuff. The side of the box equals the diameter of the circle, so ½S = the radius. The two dimensional area is πr² and we multiply that by the thickness of the cat to get the volume! How many catnip mousies in a square centimeter? Any help here? Anyone?
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Merlin77 - The mouse body would seem some sort of irregular polyhedron - a three dimensional analogue to a trapezium, with the head viewed as a separate polyhedron. Hmmm... maybe this would be simpler in four-dimensional space; too bad about that "squaring the circle" thing. Using the area of the hypersurface to find the volume of a - tesseract? Cataract? Mouseract?I'd say one catnip mouse would have a surface area of about 200 cm squared... hmm. Is a mouse more of a cylinder or a rectangular prism... ?
Actually, I would use the spherical volume formula 4/3πr3 for the cat. Then you could calculate in cubic centimeters the volume of the box and get sphere inscribed in a cube.The number of mousies per square centimeter would be a fraction.Oooo! Oooo! Circle inscribed in a square! I used to know this stuff. The side of the box equals the diameter of the circle, so ½S = the radius. The two dimensional area is πr² and we multiply that by the thickness of the cat to get the volume! How many catnip mousies in a square centimeter? Any help here? Anyone?
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Merlin77 - The mouse body would seem some sort of irregular polyhedron - a three dimensional analogue to a trapezium, with the head viewed as a separate polyhedron. Hmmm... maybe this would be simpler in four-dimensional space; too bad about that "squaring the circle" thing. Using the area of the hypersurface to find the volume of a - tesseract? Cataract? Mouseract?
Call Sheldon Cooper, quick!
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Merlin77 - I hope you didn't forget your flash drive.Haha, I actually happen to be watching the Big Bang Theory right now!
Yep - and like Bob, Raistlin is boneless.Raistlin also does a good fluffy circular shape, I think.
You would be surprised at how thin he actually is But he's got gorgeous hair to conceal itYep - and like Bob, Raistlin is boneless.
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Raven's like that tooYou would be surprised at how thin he actually is But he's got gorgeous hair to conceal it
Oh, no!!! This is pandemic now, another case of TCFNBM!!!!! Send Raven here assapRaven's like that too
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2.1Oooo! Oooo! Circle inscribed in a square! I used to know this stuff. The side of the box equals the diameter of the circle, so ½S = the radius. The two dimensional area is πr² and we multiply that by the thickness of the cat to get the volume! How many catnip mousies in a square centimeter? Any help here? Anyone?
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