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1CatOverTheLine

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Oooo! Oooo! Circle inscribed in a square! I used to know this stuff. The side of the box equals the diameter of the circle, so ½S = the radius. The two dimensional area is πr² and we multiply that by the thickness of the cat to get the volume! How many catnip mousies in a square centimeter? Any help here? Anyone?
.
 

Merlin77

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Oooo! Oooo! Circle inscribed in a square! I used to know this stuff. The side of the box equals the diameter of the circle, so ½S = the radius. The two dimensional area is πr² and we multiply that by the thickness of the cat to get the volume! How many catnip mousies in a square centimeter? Any help here? Anyone?
.
I'd say one catnip mouse would have a surface area of about 200 cm squared... hmm. Is a mouse more of a cylinder or a rectangular prism... ?
 

1CatOverTheLine

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I'd say one catnip mouse would have a surface area of about 200 cm squared... hmm. Is a mouse more of a cylinder or a rectangular prism... ?
Merlin77 Merlin77 - The mouse body would seem some sort of irregular polyhedron - a three dimensional analogue to a trapezium, with the head viewed as a separate polyhedron. Hmmm... maybe this would be simpler in four-dimensional space; too bad about that "squaring the circle" thing. Using the area of the hypersurface to find the volume of a - tesseract? Cataract? Mouseract?

Call Sheldon Cooper, quick!
.
 

catspaw66

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Oooo! Oooo! Circle inscribed in a square! I used to know this stuff. The side of the box equals the diameter of the circle, so ½S = the radius. The two dimensional area is πr² and we multiply that by the thickness of the cat to get the volume! How many catnip mousies in a square centimeter? Any help here? Anyone?
.
Actually, I would use the spherical volume formula 4/3πr3 for the cat. Then you could calculate in cubic centimeters the volume of the box and get sphere inscribed in a cube.The number of mousies per square centimeter would be a fraction.
 

Merlin77

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Merlin77 Merlin77 - The mouse body would seem some sort of irregular polyhedron - a three dimensional analogue to a trapezium, with the head viewed as a separate polyhedron. Hmmm... maybe this would be simpler in four-dimensional space; too bad about that "squaring the circle" thing. Using the area of the hypersurface to find the volume of a - tesseract? Cataract? Mouseract?

Call Sheldon Cooper, quick!
.

Haha, I actually happen to be watching the Big Bang Theory right now! :crackup:
 

dustydiamond1

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Oooo! Oooo! Circle inscribed in a square! I used to know this stuff. The side of the box equals the diameter of the circle, so ½S = the radius. The two dimensional area is πr² and we multiply that by the thickness of the cat to get the volume! How many catnip mousies in a square centimeter? Any help here? Anyone?
.
2.1
 
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